Point masses m 1 and m 2 are placed at the opposite ends of a rigid of length L, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point P on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity ω 0 is minimum, is given by : 
Text Solution
Verified by ExpertsThe correct answer is:
C
K.E. =
I ω 2
I is min. about the centre of mass
So. (m 1 ) (x) = (m 2 ) (L–x)
x = 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A solid sphere is in rolling motion. In rolling motion a body possesses translational kinetic energ…
A solid sphere is rotating freely about its symmetry axis in free space. The radius of the sphere i…
Three objects, : (a solid sphere), : (a thin circular disk) and : (a circular ring), each have t…
The moment of the force, at , about the point , is given by
A rope is wound around a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceler…
Two discs of same moment of inertia rotating about their regular axis passing through centre and pe…